In last tutorial we have seen how to design half adder circuit in labview and in this tutorial, you will learn how to design full adder circuit in labview. If you are familiar with digital logic design you must know what is the purpose and working of a full adder in digital logic design or digital systems. It is similar to the half adder we discussed in the previous tutorial. I will help you design a VI that will take to binary inputs from the user and ad the output return the sum and carry after adding them. At the start a brief introduction to full adder is provided after that a VI is designed which perform the full adder operation for three binary inputs. At the end of the tutorial you are provided with an exercise to do it by yourself.
Design full adder circuit in labview
In order to add three binary digits we will need an adder namely a full–adder circuit. This adder will take three binary digits as input and at the output it will return two outputs names as sum and carry. Implementation of a full adder is a little more difficult than half adder as you will see shortly in the programming portion. A full-adder has three inputs and two outputs, where as a half adder has two inputs and two outputs this is the main difference between half adder and full adder.
full adder circuit in labview Example
- First of all create a VI as we have discussed in tutorial 1 and save it for future use as we have been doing in all the previous tutorials. Now we have to set three Boolean inputs for the input values A, B and C to be added and two Boolean outputs to display sum and carry. For Boolean inputs we will use Boolean control i.e. a push button. On the front panel click right and from the control palette select Boolean and then select Push button as shown in the figure below,
Figure 1: Boolean controls placement
Place three such push buttons for two binary single digit inputs. Now, in order to place indicator for the binary output indication we have to place LEDs. On the front panel click right and from the control palette select Boolean and then select Round LED as shown in the figure below
Figure 2: Boolean indicator
- Place two indicators also to display sum and carry on the output. The resulting controls and indicators are shown in the figure below,
Figure 3: Control and indicators
- Now move to the block diagram for XOR, OR and AND gate placement. From the function palette on the block diagram window select Boolean and then select Exclusive Or as shown in the figure below,
Figure 4: Exclusive Or placement
- Place two such blocks as we are interested to do the XOR operation on three inputs. The output of these blocks will return the sum of the full adder output.
- At the input of the first block connect the two Boolean controls A and B and connect its output to the input of next XOR block and connect C control to the remaining input node of the second XOR gate, at the output of second XOR gate, connect the Boolean indicator i.e. the round LED you created and named as sum previously, as shown in the figure below,
Figure 5: Summing block of full adder
- To do the carry operation we have to use two AND and one OR gates. From the function palette on the block diagram window select Boolean and then select AND as shown in the figure below,
Figure 6: And block placement
- At the input of this AND gate connect the output of first XOR gate and C control, Place another and gate with inputs connect to A and B control. Now, from the function palette on the block diagram window select Boolean and then select OR as shown in the figure below,
Figure 7: Or block placement
- At the inputs of these or blocks connect the output from the two and gates and at the output node of this block connect the indication of output carry as shown in the figure below,
Figure 8: Carry block of full adder
- The complete block diagram of a full adder is shown in the figure below,
Figure 9: Block diagram
- The output of the full adder should be according to the table given below,
| A | B | C | Sum | Carry |
| 0 | 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 1 | 0 |
| 0 | 1 | 0 | 1 | 0 |
| 0 | 1 | 1 | 0 | 1 |
| 1 | 0 | 0 | 1 | 0 |
| 1 | 0 | 1 | 0 | 1 |
| 1 | 1 | 0 | 0 | 1 |
| 1 | 1 | 1 | 1 | 1 |
- Now on the front panel, set the values of both A, B and C as 0 and run the VI, both the LEDs will remain of as according to the above table, as shown in the figure below,
Figure 10: Output 1
- Now change the values and test theVI for different combinations of inputs as shown in the figure below,
Figure 11: Output 2
Exercise:
- Test the designed circuit for all the remaining combinations from the table and verify the output from the table.
<<Previous tutorial                                 Next tutorial>>